Combinatorics·OpenAI Math·Result 175·Lean formalisation listed

Talagrand’s expectation thresholds, discrete convexity, and graph decompositions

One of the 372 results in OpenAI's public mathematics catalogue, filed under combinatorics: 3 preprints, the latest dated 5 October 2026. This page quotes OpenAI's own summary of the claim, links the papers and abstracts, and will embed the animation.

Latest paper

Graph Decompositions at the Integral Expectation Threshold

5 October 2026 · PDF

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What OpenAI claims

Proves that integral and fractional expectation thresholds differ by at most a universal factor, and resolves Talagrand's discrete-convexity conjecture. An application proves the Ascoli–He–Park–Talagrand graph-decomposition conjecture: every graph's edges split into a universally bounded number of fixed pieces, each with containment threshold at most a universal constant times the original graph's integral expectation threshold. The pieces' embeddings need not agree on shared vertices. (Lean)

Papers (3)

  1. Graph Decompositions at the Integral Expectation Threshold

    · Preprint, not peer reviewed · PDF

    We prove the graph-decomposition conjecture of Ascoli, He, Park, and Talagrand. Every graph admits a partition into a universally bounded number of fixed edge pieces, each having ordinary containment threshold at most a universal constant times the original graph's integral expectation threshold. The partition is chosen before sampling the random host, and the separate embeddings of the pieces need not agree on shared vertices.

  2. Integral and fractional expectation thresholds are equivalent

    · Preprint, not peer reviewed · PDF

    We prove Talagrand's conjecture that integral and fractional expectation thresholds are within a universal constant factor, with the same covering budget.

  3. Talagrand’s discrete-convexity conjecture

    · Preprint, not peer reviewed · PDF

    We prove Talagrand's discrete-convexity conjecture. There is a universal integer k such that, whenever an arbitrary family has Bernoulli product measure at least 1-1/k, the sets not contained in a union of k members admit a cover of total cost at most 1/2 at the same density.

Status

Preprint. The papers have not been independently reviewed. Treat the result as OpenAI's claim until other mathematicians have checked it. If a video exists, it illustrates the statement; it is not the proof.

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